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n^2-33n-17=0
a = 1; b = -33; c = -17;
Δ = b2-4ac
Δ = -332-4·1·(-17)
Δ = 1157
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{1157}}{2*1}=\frac{33-\sqrt{1157}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{1157}}{2*1}=\frac{33+\sqrt{1157}}{2} $
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